Question

A digit is randomly taken from a logarithmic table.  Then the probability that the digit is 0 or 9 is (plz show me how to calculate it without range of table given) ​

Answer 1

Answer:

The probability that the digit is 0 or 9 is $\frac{1}{5}$.

Step-by-step explanation:

The probability of any event is computed by dividing the favorable outcomes of the event by the total outcomes.

Let X = a digit taken from a logarithmic table.

A logarithmic table has horizontal values from 0 to 9, i.e. a total of 10 values.

The favorable outcomes of X is, 2 {∵ 0 or 9}

Compute the value of P (X = 0 or 9) as follows:

$P(X =0\ or\ 9)=\frac{Favorable Outxomes}{Total Outcomes} \\=\frac{2}{10} \\=\frac{1}{5}$

Thus, the probability that the digit is 0 or 9 is $\frac{1}{5}$.

Learn More: https://brainly.in/question/13237064

Answer 2

Answer:

1/5

Step-by-step explanation:

total possible outcome = 10

and digit being 0 or 9 = 2

so

p(being 0 or 9 ) =2/10

1/5