A digital clock reads hours and minutes. The sum of the digits it displays at 12:00 is 3 (1+2+0+0). At 12:01 it is 4 (1+2+0+1) and so on. What is the sum of all the digits it displays from 12:00 to 12:59?
Answers
Given : A digital clock reads hours and minutes.
The sum of the digits it displays at 12:00 is 3 (1+2+0+0). At 12:01 it is 4 (1+2+0+1) and so on.
To Find : Sum of all the digits it displays from 12:00 to 12:59?
Solution:
Digits 12 is fixed from 12:00 to 12: 59
Hence sum of 1st two digits
= 60 ( 1 + 2)
= 180
Last two Digit Varies
from 00 , 01 , 09
10, 11 , 19
50 , 51 , 59
Hence 10 ( 0 + 1 + 2 + 3 + 4 + 5 ) + 6(0 + 1 + 2 + + 9)
= 10 ( 15) + 6 * 9 * 10/2
= 150 + 270
= 420
sum of all the digits it displays from 12:00 to 12:59 = 180 + 420
= 600
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Step-by-step explanation:
the fir and for most thing is recognizing the pattern
