Question

a digits of a two-digit number differ by 3.if the digits are interchanged,and the resulting number is added to its original number,we get 143.what can be the original number?

Answer 1

Answer:

Step-by-step explanation:

Let the number be 10x+y

x-y=3

x=3+y

Now the number is 10(3+y)+y

Reversed no.=10y+3+y

ATQ

10y+3+y+10(3+y)+y=143

11y+3+30+10y+y=143

22y+33=143

22y=143-33

22y=110

y=110/22=5

Original no.=85 or 58

Answer 2

let the 2 digits of no. be x and y
therefore no. =10x+y
both no's. differ by 3
therefore x-y=3..........(1)
according to second condition,
(10x+y) + (10y+x)=143
therefore, 11x+11y=143
x+y=143/11=13
x+y=13........(2)
from (1) and(2).......
2x=16
therefore x=8
x-y=3
8-y=3
y=8-3=5

thus the original no. is
10x+y=10(8)+5=80+5=85


hope it helps