Question

a dihybrid AaBb produces 5% ab gamates then what is the genotype of their parents??​

Answer 1

Answer:

Explanation:

There are four possible combinations of gametes for the AaBb parent. Half of the gametes get a dominant A and a dominant B allele; the other half of the gametes get a recessive a and a recessive b allele. Both parents produce 25% each of AB, Ab, aB, and ab.

Answer 2

The genotype of the either parent is either recessive or heterozygous as aabb or AaBb.

Explanation:

The dihybrid cross between the alleles is shown in punnet square

        AB     Ab    aB         ab

AB AABB  AABb AaAB AaBb

Ab AABb  AAbb  AaBb  Aabb

aB AaAB  AaBb  aaBB   aaBb

ab  AaBb   Aabb  aaBb  aabb

The genotype of the parent has to be hetrozygous so the genotype is AaBb. In reality there is no 5% chances of ab gametes according to law of independent assortment.

The either parent can have recessive trait crossed with heterozygous

       ab     AB    Ab     aB

ab  abab  AaBb Aabb  aaBb

ab   abab AaBb  Aabb  aaBb

ab    abab AaBb  Aabb  aaBb

ab    abaa  AaBb  Aabb  aaBb   ab gamete can be obtained in this case also.

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