Question

A dihybrid cross produces the following progeny AaBb 240 Aabb 754 aaBb 746 aabb 260. what is the distance between the two genes on the chromosome?

Answer 1

Explanation:

Total no. of progeny produced =240 + 754+746+260= 2000

$map \: distance = \frac{no. \: of \: recombinant \: offspring}{total \: no. \: of \: offspring } \times 100 \\ = \frac{4}{16} \times 100 \\ = 25$

Map distance between 2 genes on the chromosome is 25 units

Hope it helps

Pls mark me a brainliest