A dilute aqueous solution of sodium fluoride is electrolysis the products at the anode cathode are
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Answered by
50
Electrolyte: NaF (+H20) aqueous
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Electrolytic Reaction:
NaF⇌ (Na+) + (F-)
H2O⇌ (H+) + (OH-)
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Reaction at cathode:
H+ and Na+ cations move towards the cathode but H+ are deposited. This is due to the fact that hydrogen is below sodium in the electrochemical series.
(H+) + e = H
H+H= H2 (Hydrogen gas)
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Reaction at anode:
OH- and F- ions migrate towards the anode but only OH- ions gets deposited at the anode. The reason is same as above, hydroxyl is below fluorine in the electrochemical series.
(OH-) - e= OH
OH+OH= H2O + O
O+O=O2 (Oxygen gas)
______________________________
Therefore,
Products formed:
*Hydrogen at cathode
* Oxygen at anode
____________________________
Electrolytic Reaction:
NaF⇌ (Na+) + (F-)
H2O⇌ (H+) + (OH-)
_____________________________
Reaction at cathode:
H+ and Na+ cations move towards the cathode but H+ are deposited. This is due to the fact that hydrogen is below sodium in the electrochemical series.
(H+) + e = H
H+H= H2 (Hydrogen gas)
_____________________________
Reaction at anode:
OH- and F- ions migrate towards the anode but only OH- ions gets deposited at the anode. The reason is same as above, hydroxyl is below fluorine in the electrochemical series.
(OH-) - e= OH
OH+OH= H2O + O
O+O=O2 (Oxygen gas)
______________________________
Therefore,
Products formed:
*Hydrogen at cathode
* Oxygen at anode
Answered by
10
Oxygen àt anode and hydrogen at cathode.
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