Question

A dilute solution of H2SO4 is made by adding 5mL of 3N H2SO4 to 245 mL of water. The normal- ity is (A/100) N. Find the value of A.

Answer 1

Given

Initial terms --- V = 5 ml , N = 3 N. There after, 245 ml water is added.

To find

Normality of the solution

Formula

Since, number of equivalent remains same on addition of water, we use the following formula :-

$N_{1} V_{1} = N_{2} V_{2}$

Solution

Final volume after water is added = 245 + 5 = 250 ml.

Applying the formula

$N_{1} V_{1} = N_{2} V_{2} \\ \\ = > 3 \times 5 = N_{2} \times 250 \\ \\ = > N_{2} = \frac{15}{250} \\ \\ = > N_{2} = \frac{3}{50} \\ \\ = > N_{2} = \frac{6}{100} = \frac{A}{100}$

Hence, A = 6 answer