Question

A dilute solution of sodium carbonate was added to two test tubes one containing dilute HCl (Test Tube A)and other containing dilute NaOH(test tube B). the correct observation is:
(a) a brown coloured gas liberated in test tube A
(b) a brown coloured gas liberated in test tube B
(c) a colourless gas liberated in test tube A
(d) a colourless gas liberated in test tube B
it's urgent please​

Answer 1

Explanation:

A dilute solution of sodium carbonate was added to two test tubes - one containing dil HCl (a) and the other containing dilute NaOH (b).

The correct observation was :

December 30, 2019avatar

Shreyansh Deb

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ANSWER

Na

2

CO

3

+2HCl→2NaCl+H

2

O+CO

2

The colorless gas evolved is carbon dioxide. No reaction will happen in the other test tube.

Answer 2

Answer:c)

Explanation:Reaction in first test tube:

Na2co3 + HCl --> nacl + h2o +co2

There is no rxn in second test tube as both of the reactants have na+ ion in them .

We know that no rxn took place in second test tube . Therefore b) or d) can not be the right answer. We know that co2 is a colourless gas and not a brown colour gas . That is why c) is the right answer.

Hope it helps