a dimension of a closed cuboidal box are in the ratio of 5:4:3.if the total surface area is 0.94m².find the dimensions of the box
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Let the common factor of Ratio be X
Let length be 5x
Let breadth be 4x
Let height be 3x
TSA of a cuboid = 2(lb+bl+hl)
0.94m²=2(5x*4x+4x*3x+3x*5x)
0.94m²=9400cm²
9400cm²=2(20x²+12x²+15x²)
9400cm²=2*47x²
9400cm²=94x²
9400cm²/94=x²
100cm²=x²
10cm=x.
So the length of box is 5*10cm=50cm
the breadth of the box is 4*10cm=40cm
the height of the box is 3*10cm=30cm
Let length be 5x
Let breadth be 4x
Let height be 3x
TSA of a cuboid = 2(lb+bl+hl)
0.94m²=2(5x*4x+4x*3x+3x*5x)
0.94m²=9400cm²
9400cm²=2(20x²+12x²+15x²)
9400cm²=2*47x²
9400cm²=94x²
9400cm²/94=x²
100cm²=x²
10cm=x.
So the length of box is 5*10cm=50cm
the breadth of the box is 4*10cm=40cm
the height of the box is 3*10cm=30cm
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10 cm
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