Question

A dinner party is to be fixed for a group of 100 persons in this party 50 persons do not prefer fish, 60prefer chicken and 10 do not prefer either chicken or fish. The number of persons who prefer both the fish and chicken is

Answer 1

    The number of persons who prefer both fish and chicken is= 20

• Persons do not prefer either fish or Chicken = 10.
• Persons do not prefer fish = 50 = (person only prefer fish + do not prefer either fish or chicken)  ==> 50 = X+10. X = 40.
• Person only prefer Chicken = 40
• person prefer Chicken = 60.
• So, person prefer both fish and chicken= 60 - 40 =20.