A diode has potential drop of 0.5 volt in forward bias. The maximum current that can flow through diode is 10mA. Then find the resistance connected in series with diode so that set up can be connected to a battery of 1.5 volt ?
Answers
Answer:
ok the answer must be
Explanation:
first you have to add 0.5 volt in 10mA
and then you get answer 11 .5 volt that is when you convert 11.5 into decimal form your answer is 1.5 volt
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A diode has potential drop of 0.5 volt in forward bias. The maximum current that can flow through diode is 10 mA.
We have to find the resistance connected in series with diode so that set up can be connected to a battery of 1.5 volt
solution : potential across resistance = emf + potential across diode
when diode is connected in forward bias condition, a negative voltage is applied.
i.e., potential across diode = -0.5 volt
⇒V = 1.5 volt - 0.5 volt = 1 volt
as diode is connected in series with resistance.
so, current through diode is equal to current through resistance.
current through diode , i = 10 mA = 0.01 A
now, current through resistance = i = 0.01 A
from Ohm's law,
R = V/i = 1/0.01 = 100 Ω
Therefore the resistance is 100 Ω