A diogonal of a parallelogram divides it into two congruent triangles
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Let the parallelogram be ABCD
In triangles ABC and BCD,
AC is the common side
AB=CD
BC=AD
Thus Triangle ABC is congruent to BCD
Similarly while the parallelogram is divided by BD the two triangles formed are congruent
Thus the diagonals of a parallelogram divide it into 2 congruent triangles
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In triangles ABC and BCD,
AC is the common side
AB=CD
BC=AD
Thus Triangle ABC is congruent to BCD
Similarly while the parallelogram is divided by BD the two triangles formed are congruent
Thus the diagonals of a parallelogram divide it into 2 congruent triangles
PLZ MARK THIS AS THE BRAINLIEST ANSWER
HOPE THIS HELPS U
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