Question

A dipole consisting of an electron and a proton separated by a distance of 4×10-10m is situated in an electric field of intensity 3×10^5Nc-1 ata n angle 30 with the field .claclute the dipole moment and the torque acting on it charge on an electron =1.602×10^-19 c

Answer 1

Answer:

Dipole moment of system of charge is

$P = 6.4 \times 10^{-29} Cm$

Torque on the dipole is given as

$\tau = 9.6 \times 10^{-24} Nm$

Explanation:

As we know that dipole moment of a system of charge is given as

$P = q.d$

here we know that

$q = 1.6 \times 10^{-19} C$

$d = 4\times 10^{-10} m$

now we have

$P = (1.6 \times 10^{-19})(4 \times 10^{-10})$

$P = 6.4 \times 10^{-29} Cm$

Torque on the dipole is given as

$\tau = P \times E$

$\tau = PE sin\theta$

$\tau = (3\times 10^5)(6.4 \times 10^{-29}) sin30$

$\tau = 9.6 \times 10^{-24} Nm$

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Topic : Torque on Dipole

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