Question

A dipole consisting of an electron and proton seperated by a distance 4×10-¹⁰m calculate the dipole moment

Answer 1

Answer:

6.4 x 10^(-29)

Explanation:

Dipole moment is given by the product of product of magnitude of charge on any of them( since both are equal ) and distance between them.

Here,

Charge on each = 1.6 x 10$^{-19}$

Distance in them = 4 x 10$^{-10}$

Therefore, dipole moment here is -

= > 4 x 10^(-10) x 1.6 x 10^(-19)

= > 4 x 1.6 x 10^(-10) x 10^(-19)

= > 6.4 x 10^(-10-19)

= > 6.4 x 10$^{-29}$

Answer 2

Given ,

Charge (q) = 1.6 × (10)^{-19} C

Distance (2a) = 4 × (10)^{-10} m

We know that , the electric dipole moment is given by

$\boxed{ \sf{\vec{P} = q \times 2a}}$

Thus ,

P = 1.6 × (10)^{-19} × 4 × (10)^{-10}

P = 6.4 × (10)^{-29} C.m

$\sf \therefore \underline{The \: electric \: dipole \: moment \: is \: 6.4 \times {(10)}^{ - 29} \: C.m}$