Question

A dipole is formed by two charges 5 uc and -5uc at a distance 8mm.findthe electricfield at. (a)apoint 25cm away from center of dipole along its axial line (b)a point 20cm away from center of dipole along its equatorial line​ [please some one ans it]

Answer 1

Answer:

Electric field at axial position of dipole is 46080 N/C

electric field at equitorial position of dipole is 45000 N/C

Explanation:

As we know that dipole moment is given by formula

$P = qd$

here we have

$q = 5\mu C$

$d = 8 mm$

$P = (5 \times 10^{-6})(0.008)$

$P = 4 \times 10^{-8} Cm$

Part a)

Electric field at axial point of the dipole is given as

$E = \frac{2kP}{r^3}$

here we know that

r = 25 cm

$E = \frac{2(9 \times 10^9)(4 \times 10^{-8})}{0.25^3}$

$E = 46080 N/C$

Part b)

At equitorial position of the dipole we will have

$E = \frac{kP}{r^3}$

here we have

r = 20 cm

$E = \frac{(9\times 10^9)(4 \times 10^{-8})}{0.20^3}$

$E = 45000 N/C$

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Topic : Electric field due to dipole

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