Question

A dipole is formed by two charges of 5 and minus 5 and a distance of 8 find the electric field at a point 25 CM away from the entry of dipole along its axial line

Answer 1

Dear Student,

● Answer -

E = 46.08 N/C

◆ Explanation -

# Given -

q = 5 uC = 5×10^-6 C

d = 8 cm

x = 25 cm

# Solution -

Electric field at a point 25 cm away on axis of dipole is -

E = (1/4πε0) × 2qd/x^3

E = 9×10^9 × 2 × 5×10^-6 × 8 / 25^3

E = 46.08 N/C

Hence, electric field along the axis of dipole at 25 cm is 46.08 N/C.

Thanks dear. Hope this helps you..