Physics, asked by Kunjalbabbar7388, 11 months ago

A dipole is present in an electrostatic field of magnitude 10^6 n/c in the work done in rotating it from position of stable equilibrium position of unstable equilibrium

Answers

Answered by shreenilogu
2

Answer:

Explanation: this is not so exact

The condition of stable equilibrium is achieved when the direction of extrernal electric field is parallel to the direction of the dipole moment.

Hence, Potential Energy = -PEcos?

Since ?=0, cos ?=1

Thereferoe, potential energy=PE=maximum

In unstable equilibirum, the direction of the electric field is antiparallel to the direction of dipole moment.

therefore, ?=180 degrees. cos?= -1

hence, Potential enegy = -PE

Hence, total work done = Initial energy - final energy = PE - (-PE) = 2PE

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