Physics, asked by rihanna50, 11 months ago

A dipole of dipole moment is rotated inside a uniform electric field from its stable equilibrium position to unstable equilibrium position slowly. Then work done by external agent is?

Answers

Answered by premsai2141
4

Answer:

 stable equilibrium the angle between p and E , θ₁ = 0° 

For unstable equilibrium,θ₂ = 180° 

Work done in rotating the dipole from angle θ₁ to θ₂ 

W = pE(cosθ₁-cosθ₂) = pE(cos0°-cos180°)

= 2pE.

Please mark it as brainliest

Answered by jassimahi8967
0

Answer:

Work done by external agent = 2PE

A pair of force which is equal in magnitude with opposite direction , and displaced by perpendicular distance or moment is known as a couple.

For an electric dipole p in a uniform field E we write the work done by external agent in rotating dipole as dW= pEcosθ dθ

Step by step explanation :

If the dipole is rotated from an angle θ_{1} to θ{2}

then work done by external force is given by

       W = pE [cos θ_{1} - cos θ{2} ]

For stable equilibrium the angle between  p and E , θ_{1} =0°

For unstable equilibrium θ_{2} =180°

work done in rotating the dipole from θ_{1} to θ_{2}

W =pE (cos θ_{1} - cos θ_{2} )

 = pE ( cos 0° - cos 180° )

    = pE ( 1 - ( -1))

   = 2pE

From the above we conclude that work done by external agent =

        2pE.

For more information visit :

https://brainly.in/question/2622890?msp_srt_exp=4

https://brainly.in/textbook-solutions/q-9-work-external-agent-turn-electric-dipole-3

#SPJ3

Similar questions