A disc having a uniform charge density σ and radius R is placed on x−y plane with centre at the origin . Find the electric potential at a point on z - axis at a distance 10m from centre . σ=16∈0,R=1m
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(b) 0.4
Explanation : potential due to whole disc = σ2∈0[R2+x2−−−−−−√−x]
Since x > > R
V=σ2∈0[x(1+R2x2)12−x]
V=σ2∈0[x+R22x−x]
V=σR24∈0x
V=(16∈0)14∈010=0.4.
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