Question

a disc of large radius having moment of inertia 10kgm^2 is rotating with angular velocity 10rad/sec , about an axis perpendicular to the plane and passing through it's centre .if a point mass of 1kg I'd gently put on the disc at 2m from the centre of disc then it's new angular velocity will be ?​

Answer 1

Answer:

Moment of inertia I=

2

mr

2

=

2

10×0.2

2

=0.2 kgm

2

Angular acceleration α=

I

τ

=

0.2

10

=50 rad/s

2

Initial angular velocity w

i

=0

Using w

f

=w

i

+αt

Or w

f

=0+50×6=300 rad/s