A disc of mass 2 kg and radius 10 cm carrying a charge uniformly distributed over it, is rotating with angular speed 2 rad/s about an axis passing through its centre and perpendicular to its plane. The magnetic moment will be
Options:
20 nA m2
10 nA m2
2 nA m2
40 nA m2
Answers
Answered by
7
answer:
20nA m2
explanation:
we know that,
M/L = q/2m
M=q/2m x mr^2w/4
M=qr^2w/4
M=4x10^-6x10^-2x2/4
M=20nA m2
Answered by
2
Answer:
20nA m2
explanation:
we know that,
M/L = q/2m
M=q/2m x mr^2w/4
M=qr^2w/4
M=4x10^-6x10^-2x2/4
M=20nA m2
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