Question

A disc of mass 400gm is rolling on horizontal surface with a velocity 2m/s find total kinetic energy

Answer 1

k.e = 1/2mv2
mass=400/1000=0.4kg
velocity =2m/s
kinetic energy =0.4×2×2/2
k.e=0.8 joule
here is ur answer

Answer 2

Formula :

Kinetic energy = 1/2 × mass × ( velocity )²

Given :

Mass = 400 g

         = 400 / 1000 kg

         = 4 / 10 kg

         = 0.4 kg

Velocity = 2 m/s

Find the kinetic energy

K = 1/2 × 0.4 kg × ( 2 m/s )²

= > K = 0.2 kg × 4 m²/s²

= > K = 0.8 kg m²/s²

= > K = 0.8 J

ANSWER:

The kinetic energy is 0.8 J