Question

A disc of mass 5 kg. and radius 50 cm rolls on the grounds at the rate of 10m/s.
Calculate the KE of the disc.
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Answer 1

Answer:

500

Explanation:

ke = 1/2*mv`2

1/2*5*10*10

Answer 2

Explanation:

Total Kinetic energy is 375 J.

Step-by-step explanation:

Given : A disc of mass 5 kg and radius 50 cm rolls on the ground at the rate of 10 m/s.

To find : Calculate K. E ?

Solution :

Mass is m=5 kg

Radius is r=50 cm=0.5 m

Velocity is v=10 m/s

Moment of Inertia of Disk is given by,

$M=\frac{1}{2}m r^2$

$M=\frac{1}{2}\times 5\times (0.5)^2$

$M=0.625\ kgm^2$

Total Kinetic energy is given by,

$KE=\frac{1}{2}(M(\frac{v}{r})^2+mv^2)$

$KE=\frac{1}{2}(0.625(\frac{10}{0.5})^2+(5)(10)^2)$

$KE=\frac{1}{2}(250+500)$

$KE=\frac{1}{2}(750)$

$KE=375\ J$

Therefore, Total Kinetic energy is 375 J.

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