Question

A disc of radius 2m and mass 200kg is acted upon by a torque 100N-m. Its angular acceleration would
be
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Answer 1

Answer:

I=1/2*200*2*2=400kgmsq

tau=i*alpha

hence, alpha=100/400=0.25

Answer 2

A disc whose radius 2m and mass 200kg is acted upon by a torque of 200N-m ,then its angular acceleration is calculated as-

1. Since we know that for a uniform rotating disc, T=I×a .

2. Where T= torque, I= moment of inertia of disc about rotating axis and a = angular acceleration.

3. Since I = MR^2 for disc around its perpendicular axis passing through its centre. And I = 200×2×2 = 800kg-m^2.

4. Therefore, a= T/ I = 100/ 800 = 0.125 rad/sec^2.