A disc of radius R, and mass M. IfR/2 part cut from disc find mass of cut part and reaming part.
Answers
Answered by
3
Answer:
Total disc
=
2
MR
2
As mass is proportional to area, M
Removed
=
4
M
Now, about the same perpendicular axis:
I
Removed
=
4
M
2
(R/2)
2
+
4
M
(
2
R
)
2
=
32
3MR
2
⇒I
Remaining Disc
=I
Total
−I
Removed
=
2
MR
2
−
32
3MR
2
=
32
13MR
2
Answered by
0
=I
Total disc
=
2
MR
2
As mass is proportional to area, M
Removed
=
4
M
Now, about the same perpendicular axis:
I
Removed
=
4
M
2
(R/2)
2
+
4
M
(
2
R
)
2
=
32
3MR
2
⇒I
Remaining Disc
=I
Total
−I
Removed
=
2
MR
2
−
32
3MR
2
=
32
13MR
2
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