A disc on which a player spins an arrow twice. The dics has numbers from 1 -6 . The fraction
a/b is formed where 'a' is the number of sector on which the arrow stops on first spin and 'b' is the number of sector in which the arrow stops on the second spin. on each spin , each sector has equal chance of selection by the arrow. Find the probability that the fraction a/b>1
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Answered by
56
i accidentally calculated for a/b<1. u just need to do 1-15/36 to get the actual answer that is 21/36
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I'll tell this. make a sample space, it's like the total outcomes u can have. Compare it with a situation of a dice
The first arrow can land on any of the six. so the possibility is from 1 to 6 . Similarly, the second arrow can land on any of them
so there's again 1 to 6
i made the pairs
and then chose the favourable outcomes where a/b is less than one
that's it
ohh can you message me the solution?
actually I'm too weak in maths
I just did. If you want i can. But after a few hours
oh okay send me whenever you have time
Answered by
80
here is the answer..hope it helps
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