Question

A disc on which a player spins an arrow twice. The fraction a divided by b is formed , where a is the number of sector on which arrow stops on the frst spin and b is the number of sector in which the arrow stops on second spins , each sector has equal chance of selection by the arrow , find the probability that the fraction a divided by b >1 The disc contains 6 divisions and each division contains 1,6,5,4,3,2 and the arrow is in number 6

Answer 1

hope this helps you need anymore help i will answer it for you.
Thanks, hopi 

Answer 2

For  a  ÷ b  >  1, when a = 1, b can not take any  value,

a = 2, b can take 1 value,

a = 3, b can take 2 values

a = 4, b can take 3 values

When a = 5, b can take 4 values,

a = 6, b can take 5 values

Total possible outcomes = 36

P  ( a  ÷ b  >  1  ) = $\bf\huge\frac{1+2+3+4+5}{36}$

= $\bf\huge\frac{15}{36}$

= $\bf\huge\frac{5}{12}$