Physics, asked by prasadanthony24, 1 year ago

A disc rotates about its axis of symmetry in a horizontal plane at a study rate of 3.5 revolutions per second a coin placed at a distance of 1.25cm from the axis of rotation remains at rest on the disc the coefficient of friction between the coin and the disc : (g = 10m/sq )

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Answered by abhinav27122001
0
Here's your answer mate
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ashish55587: what is f here
abhinav27122001: f is the frequency
ashish55587: can you explain me
abhinav27122001: what
ashish55587: how at place of omega it is 4π²f²
abhinav27122001: omega^2=(2πxfrequency)^2
abhinav27122001: =4π^2xf^2
ashish55587: is it formula
abhinav27122001: Of course
Answered by ashish55587
0
see the attachment⬇⬇⬇

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