a discrete random variable x has mean equal to 6 and variance equal to 2. if it is assumed that the underlying distribution x is binomial,what is the probability that 5<=x<=7? please give step by step explanation or handwritten picture
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Suppose a variable X can take the values 1, 2, 3, or 4. The probability that X is equal to 2 or 3 is the sum of the two probabilities: P(X = 2 or X = 3) = P(X = 2) + P(X = 3) = 0.3 + 0.4 = 0.7. Similarly, the probability that X is greater than 1 is equal to 1 - P(X = 1) = 1 - 0.1 = 0.9, by the complement rule.
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Suppose a variable X can take the values 1, 2, 3, or 4. The probability that X is equal to 2 or 3 is the sum of the two probabilities: P(X = 2 or X = 3) = P(X = 2) + P(X = 3) = 0.3 + 0.4 = 0.7. Similarly, the probability that X is greater than 1 is equal to 1 - P(X = 1) = 1 - 0.1 = 0.9, by the complement rule.
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