a dish fault hundred bacteria it is known that the bacteria as double in every hour how many bacteria will be present after each number of hours 1 hour 5 hour and Hour 3 by 2 hours
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It is given that the number of bacteria doubles every hour.
Therefore, the number of bacteria after every hour will form a G.P.
with first term (a=30) and common ratio (r=2)
∴a3=ar2=(30)(2)2=120
Therefore, the number of bacteria at the end of 2nd hour will be 480.
a5=ar4=(30)(2)4=480
and an+1=arn=(30)(2)n
Thus the number of bacteria at the end of nth hour will be (30)(2)n
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