A dish of 10g is kept horizontally in air by firing bullets of 5g each at rate of 100per s . if bullets rebound with same speed what is velocity which bullets are fired ??
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Answered by
17
Heya......!!
Change in momentum on 1 bullet = - mv-mv => - 2mv
Change in momentum of dish = + 2mv
Change in momentum of dish in one sec =>> Force ,F = 100 ( 2 mv )
we know that F = mg .
so ,,,
100 (2 mv ) = mg
100 ( 2×5×10^-3 ×V ) = 10 × 10^-3 g
V ( velocity of bullet ) =➡ 0.098 m/s .
HOPE IT HELPS U
Change in momentum on 1 bullet = - mv-mv => - 2mv
Change in momentum of dish = + 2mv
Change in momentum of dish in one sec =>> Force ,F = 100 ( 2 mv )
we know that F = mg .
so ,,,
100 (2 mv ) = mg
100 ( 2×5×10^-3 ×V ) = 10 × 10^-3 g
V ( velocity of bullet ) =➡ 0.098 m/s .
HOPE IT HELPS U
Answered by
1
change in momentum = Force
∆p/t = F
F = mnv /1
Force = mnv .
∆p/t = F
F = mnv /1
Force = mnv .
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