A dishonest dealer professes to sell his goods at cost price but uses a false weight and thus gains 20%. For a kilogram he uses a weight of?
Answers
Answered by
3
Answer:
ANSWER
Given that: %Gain =6
47
18
=
47
300
% Gain=(
Correct weight
Correct weight-Incorrect weight
)×100
∴ For 1 kg,
⇒
47
300
=(
1
1−IW
)×100
⇒IW=1−
47
3
=
47
44
kg=940gm
Answered by
0
Answer:
800 gm
Step-by-step explanation:
let the false weight be x grams
then, gain%= (1000-x)/x * 100
so
20=(1000-x)/x * 100
by cross multiplying
x/4=1000-x
x=4000-4x
5x=4000
x=800 gms
therefore the actual weight the dealer uses in place of one kg is 800gms
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