Question

A dishonest milkman adds water to the milk he sells. He
had two containers. One of them had water which
contained 30% milk. Let this be called mixture A. The
other one had milk which contained 20% water Let this
be called mixture B. He decided to mix the two mixtures
in a third container. Doing so, he got a mixture that
contained 60% milk What Isthe ratio of the volumes of
mixture A and mixture B?​

Answer 1

Answer:

2:3

Step-by-step explanation:

2:3 is the correct answer of this question.

Answer 2

Given:

Percentage of milk in mixture A=30%

Percentage of water in mixture B=20%

Percentage of milk in the final mixture=60%

To find:

The ratio of the volumes of mixture A and B in the final mixture

Solution:

The ratio of the volumes of mixture A and B in the final mixture is 2:3.

We can find the ratio by following the given steps-

We know that the ratio can be obtained by using the concept of alligation.

We are given that the percentage of milk in mixture A is 30% and the percentage of water in mixture B is 20%.

So, the percentage of milk in mixture B=100-percentage of water

=100-20=80%

Now, the final mixture obtained has 60% milk in it.

Let the ratio of mixture A and B in the final mixture be m:n.

Using alligation, we know that

m=Percentage of milk in mixture B-percentage of milk in the final mixture

m=80%-60%

m=20%

Similarly, n=Percentage of milk in the final mixture-percentage of milk in mixture A

n=60%-30%

n=30%

So, m:n=20%:30%

m:n=2:3

Therefore, the ratio of the volumes of mixture A and B in the final mixture is 2:3.