Question

a dishonest milkman claims to sell milk at cost price but the milk is adulterated with 20% of water . what is his profit percent

Answer 1

Answer:

16.6%

Step-by-step explanation:

Let C.P. of 1 litre milk be Rs. 1

Then, S.P. of 1 litre of mixture = Rs. 1, Gain = 20%

C.P. of 1 litre mixture = Rs. (100 / 120 × 1)

 = 5 / 6

Ratio of milk and water is

5/6–0:1–5/6 = 5/6:1/6

% of water in milk = 1/6*100 = 16.6%

Answer 2

Answer:

Correct option is C)

According to the question,

Let's assume milkman has 100 liter of milk, If he added x liter of water, the percentage of water in the mixture=

(100+x)

x

×100

The milk gain 25%, he must have added 25 liter water in 100 liter of milk. Then the percentage of water in the mixture=

(100+25)

25

×100=20%

In the new mixture, If the milk is 80% then 80% of total mixture should be 100 liter

(100+x)×

100

80

=100

8x=200

x=25

Then, the percentage of water in the mixture =

(100+25)

25

×100=20%