A dishonest milkman purchased milk at Rs 10 per liter and miced 5blitres of water in it . by selling the mixture at the rate Rs 10 per liter,he earns profit of 25%. the quantity of mixture that he had was?
Answers
Answer:
30 liters
Step-by-step explanation:
he mixed 5 liters of water
which is 1/4th of total
that means:- 5*4=20
so,20 liter is the answer
Given:
The cost of milk = Rs. 10 per litre
Amount water mixed in the mixture by the milkman = 5 litres
The selling price of the mixture = Rs. 10 per litre
Profit earned while selling the mixture = 25%
To find:
The original quantity of mixture that the milkman had
Solution:
We know that pure water doesn’t cost anything
∴ The cost price of pure water will be = Rs. 0
According to the question, we can get the cost price of the mixture as:
The C.P. of the mixture =
[ Formula used for the above calculation: ]
Now, by using the rule of mixture and alligations, we get
Milk (cost per litre) Water (cost per litre)
10 0
8 (Mixture)
(8 - 0) (10 - 8)
8 2
∴ The ratio of milk and water in the mixture = 8 : 2 = 4 : 1
Let "x" litres be the quantity of the mixture that the milkman had.
We have been given the quantity of water in the mixture as 5 litres, therefore to find the quantity of the mixture we can apply the following calculation:
The quantity of water in the mixture = [ the parts of water in the milk & water ratio ] * [ the original quantity of the mixture ]
On substituting the values, we get
⇒
⇒
⇒ 25 litres
Thus, the quantity of mixture that the milkman had was 25 litres.
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