Question

A dishonest shopkeeper makes a cheating of 20% at the time of buying the goods and 40% cheating at the time of selling the goods. He promise to sell his goods at 10% loss. Find the profit %

Answer 1

Answer:

57.5%

Step-by-step explanation:

Let the cost price of the goods be x

Since he promises to sell it on the loss of 10%

Therefore, the selling price of the goods = x-(x/10) = 9x/10

Sine the shopkeeper cheats 20% on selling

Therefore he bought the goods in x-(20x/100) = 4x/5

On selling he cheats 40%

Therefore original selling price of the goods = 9x/10 + (9x/10)(40/100)

                                                                         = (9x/10)(1+2/5) = 63x/50

Therefore, profit = (63x/50) - (4x/5) = 23x/50

Profit percentage = [(23x/50)÷(4x/5)]×100 = 57.5%

Answer 2

Answer: 30%

e.g. if he has  100 us dollars= at the time of buying  he will us

80% of his dollar 100%-20%)

(100-20)= 80 DOLLARS

at selling makes 40%  (100%+40%=140%)

140/100 multiple 80 dollars =112 dollars

profit= 112 dollars - 80 dollars( selling price -buying price )= 32 dollars

32/80 multiple by 100%=  40%

40%-10% = 30%

Step-by-step explanation: