Question

a disk roll on table the ratio of its kinetic energy of rotation to the total k. e​

Answer 1

Answer:

2/5.

Explanation:

The rotational kinetic energy is given by the formulae of (1/2)*I*ω^2 where ω is the angular velocity of the disk. Since the moment I of the disk is know as 2/5MR^2 where M is the mass of the disk and R is the radius of the disk. So, the rotational kinetic energy will be 1/5MR^2ω^2 or 1/5Mv^2. Where the body is rolling without any slip.

While the total kinetic energy is know as = 1/2M*v^2. Where M is the mass of the body and v is the velocity of the body.Hence, the ratio of kinetic energy of rotation to the total kinetic energy will be given as K=2/5.

Answer 2

Answer:

Explanation

Refer to image attached below :)