Question

A disk unit has 24 recording surfaces. It has a total of 14000 cylinders. There is an average of 400 sectors per track. Each sector contains 512 bytes of data. What is the data transfer rate at a rotational speed of 7200 r.P.M.?

Answer 1

Hii Mate!!


400 sectors / track

512 bytes/sector

Rotational speed = 7200 rpm

7200 rotations →→  60 sec

1 rotation?



= 60*1

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7200 ROTATIONS 





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120 rotations / sec 

Data transfer rate = (120 rotations / sec) * (1 track / rotations) ** (400 sectors / track) ** (512 bytes / sector)

 = 24576000 bytes / second

 = 24.576 MB / second

Regards Vishal__________(BhamBhamBhole)
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