Question

a displacement of a particle executing SHM is given by y=10sin(3t+π/3)m and 't' is in seconds. the initial displacement and maximum velocity of the particle are respectively​

Answer 1

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Answer 2

Answer:

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Explanation:

Answer

Initially t=0;y=10sin( π/3)

=10× √3/2

=10 √3/2m

v= dy/dt

=60cos(3t+ π/3)

At t=0⇒60×cos(π/3)

=30m/s