Question

A displacement of a particle starting from rest t( t=0)is given by x=[6t2-t3) calculate the time at which the particle will attain 0 velocity again

Answer 1

Given,

x = 6t^2 - t^3.

velocity = dx/dt

dx/dt = 12t - 3t^2

so particle will attain velocity = 0

=) V = 12t - 3t^2

=) put V = 0

we get ,

=) 3t(4 - t) = 0

we get t = 0 and t = 4 sec

so at t = 0 particle starts and again attains zero velocity at t = 4 sec ..

____hope it will help u __________

◆ shreya ^_^

Answer 2

Answer: 4sec

Step-by-step explanation:

Given is the s = f(t)

s = 6t²-t³

As velocity is the first derivative of displacement

i.e., v = ds/dt

= d/dt (6t²-t³)

= 12t - 3t²

Since velocity is reaching zero, eqn be equated to zero

v = 12t² - 3t² = 0

12t² = 3t²

t = 4 sec

And here's the ans.

Hope it helps....