Question

A displacement wave is represent by y= 0.025x10-3 sin ( 500t -0.025x) .where y,t,x are in cm, sec and metres respectively. Deduce amplitude ,period, angular frequency, wavelength . Also deduce the amplitude of particle velocity .

Answer 1

The standard equation of displacement wave is represented by,

y = A sin(kx - ωt + Ф)

The given equation is

y= 0.025x10-3 sin ( 500t -0.025x)

comparing the standard equation with the given equation we get,

Amplitude, A = 0.025 x 10⁻³ cm

ω = 2πf = 500

=>Frequency,  f = 500/2π = 79.5 Hz

Time period is defined as the inverse of frequency,

=> Time period, T = 1/f = 1/79.5 = 0.012 sec

k = 2π/λ = 0.025

=> wavelength, λ = 2π/k = 2π/0.025 = 251.32 m

I hope this answer helps you, please feel free to ask any doubts regarding this in the comment section.

Answer 2

Answer:

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