Question

A distance around a rectangular field is 56m the length is 8m less than twice its breadth so find length and breadth ?

Answer 1

Perimeter=56m
Length=2b-8m
Breadth=b

Perimeter=2(l+b)
56=2(2b-8+b)
56/2=2b-8+b
28=3b-8
28+8=3b
3b=36
b=12
L=2(12)-8
L=24-8
L=16.

Answer 2

Step-by-step explanation:

Answer:

${\sf{\green{\underline{\overline{Given:-}}}}}$

ʟᴇᴛ ᴛʜᴇ ʙʀᴇᴀᴅᴛʜ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ(ʙ) = xᴍ

ᴛʜᴇɴ ʟᴇɴɢᴛʜ(ʟ) = (2x-8) ᴍ

${\sf{\pink{\underline{\overline{To \: find:-}}}}}$

ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ = 56 ᴍ

${\sf{\red{\underline{\overline{Solution:-}}}}}$

$\sf \blue{⇒  2(l+b) = 56}$

$\sf \pink{⇒  2(2x-8+x) = 56}$

$\sf \purple{⇒  3x-8 = 28}$

$\sf \green{⇒  3x =28+8}$

$\sf \blue{⇒  x = 36/3 = 12 m}$

$\sf \fbox \orange{Therefore :-}$

ʟᴇɴɢᴛʜ(ʟ) = 2x-8 =2×12 - 8 =16 ᴍᴇᴛᴇʀs.

ʙʀᴇᴀᴅᴛʜ(ʙ) = x = 12 ᴍᴇᴛᴇʀs.

${\sf{\pink{\underline{\overline{❀Tʜᴀɴᴋs \: !!}}}}}$