Question

A distance of 2m separates the point charges of +5x10-19 C and +5x10-19C. Find the point on the line joining the two charges at which electric
field intensity is zero.

Answer 1

Explanation:

The electric field intensity is zero inbetween where both have same magnitude and acts opposite.

5 x 10^-19/x² = 5 x 10^-19/(2 -x)²

1/x² = 1/(2 - x)²

(2 - x)². = x²

4 + x² - 4x = x²

4 = 4x

x = 1m

at the mid point on the line joining two charges.