Math, asked by RadiGad, 1 year ago

a district contains 64000 inhabitants. if the population increases at the rate of 2.5 per annum, find the number of inhabitants at the end of 3 years.

Answers

Answered by praveen2604
22

population after one year=64000+64000×25÷1000
=64000+1600=65600
population after second year=65400+65400×1÷40
=65400+1635=67035
population after third year=67035+67035×1÷40
=67035+1675.875=67710.875
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