A district contains 64000inhabitaints. If the population increase at the rate of 2×1×2 per anuum find the number of inhabitants at the end of 3year
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Initial Population (IP) = 64000
Rate (r) = 2.5% per annum
Time (n) = 3 years
At the end of 3 years:
Population = IP * (1+r/100)^n
= 64000*(1+2.5/100)^3
=64000* 1.025^3
= 68921 people
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Hey dude here is your answer
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a district has 64000 inhabitants
the number of inhabitants end of the year is 64000 × 3
19200
__________________
a district has 64000 inhabitants
the number of inhabitants end of the year is 64000 × 3
19200
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