Question

A divalent metal ‘A’ combines with bicarbonate and forms a compound.
What will be the formula obtained by the compound?

Answer 1

Answer:

An element A is tetravalent hence oxidation number of A can be A

+4

Element B is divalent hence oxidation number of B can be B

2−

According to the cris-cross method formula of the compound will be : A

2

B

4

or AB

2

Hence, te correct option is C

Answer 2

Answer:

divalent metal is

${m}^{ + 2} \\ and \: bicarbonate \: is \: \\ {hco3}^{ - 1} \\ the \: formula \: obtained \: is \: m(hco3)2$