Chemistry, asked by Deathwish, 11 months ago


A divalent metal M reacts with HCI to form bubbles of a colorless gas . Similar bubbles are
also observed when metal M reacts with NaOH solution. How will you test this gas?Write
balanced chemical equations of metal M with HCl and NaOH



Plz answer me as soon as possible

Answers

Answered by Anonymous
18

Answer:

The divalent element M is Zn.

Zn(s) + dil. HCl(aq) ⇒ ZnCl₂(aq) + H₂↑(g)

The produced gas can be identified by bringing a burning splinter near the gas (mouth of the reaction vessel). The gas burns with a pop sound, hence it is hydrogen gas.

Answered by varshini1101
2

The produced gas is hydrogen.

Keep the match stick near the mouth of beaker, when the gas is released out of the beaker, the match stick put off And gets pop sound.

Hence proved.

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