Question

A diver allows himself to fall off a platform 11.7 m above the water into a pool which is 3.32 m deep. How fast is he going when he hits the waters surface?

Answer 1

Answer:

15.3 m/s

Explanation:

A diver allows himself to fall off a platform 11.7 m above the water into a pool which is 3.32 m deep. How fast is he going when he hits the waters surface?

diver fall off a platform 11.7 m above the water into a pool

We need to find Velocity when he hits the waters surface

Assuming water top surface

Distance = 11.7 m

U = 0

a = g = 10 m/s

V² - U² = 2aS

=> V² = 2 * 10 * 11.7

=> V = 15.3 m/s