A diver initially moving horizontally with speed v dives off the edge of a vertical cliff and lands in the water a
distance d from the base of the cliff. How far from the base of the cliff would the diver have landed if the diver
initially had been moving horizontally with speed 2v?
(A) d (B) 2d (C) 2d (D) 4d
Answers
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Answer:
v^2 is directly proportional to d
Explanation:
so it is 4d
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