Math, asked by anatauqir12, 1 month ago

A diver is at −5 ft with respect to the sea level when he starts descending.
If he descends by 10 ft every 6 minutes, what is his position, with respect to the sea level, after 30 minutes?

The position of the diver before the descent =
ft

The change in his position during the descent (in 30 minutes) =
ft

The final position of the diver at the end of 30 minutes =
ft

Answers

Answered by himanshigarg076
3

Step-by-step explanation:

The position of the diver before the descent = −5 ft

If a diver dives down 10 ft every 6 minutes, the change in his position in 6 minutes = −10 ft

The change in diver's position during the descent (in 30 minutes) = 5 × (−10) ft = −50 ft

The final position of the diver after 30 minutes= (−5) + (−50) ft= −(5 + 50) ft= −55 ft

Answered by 10621
0

Answer:

−5 ft, −50 ft, −55 ft

The position of the diver before the descent = −5 ft

If a diver dives down 10 ft every 6 minutes, the change in his position in 6 minutes = −10 ft

The change in diver's position during the descent (in 30 minutes) = 5 × (−10) ft = −50 ft

The final position of the diver after 30 minutes = (−5) + (−50) ft

= −(5 + 50) ft

= −55 ft

Hope u have a great day!!

Similar questions