A diver is at −5 ft with respect to the sea level when he starts descending.
If he descends by 10 ft every 6 minutes, what is his position, with respect to the sea level, after 30 minutes?
The position of the diver before the descent =
ft
The change in his position during the descent (in 30 minutes) =
ft
The final position of the diver at the end of 30 minutes =
ft
Answers
Answered by
3
Step-by-step explanation:
The position of the diver before the descent = −5 ft
If a diver dives down 10 ft every 6 minutes, the change in his position in 6 minutes = −10 ft
The change in diver's position during the descent (in 30 minutes) = 5 × (−10) ft = −50 ft
The final position of the diver after 30 minutes= (−5) + (−50) ft= −(5 + 50) ft= −55 ft
Answered by
0
Answer:
−5 ft, −50 ft, −55 ft
The position of the diver before the descent = −5 ft
If a diver dives down 10 ft every 6 minutes, the change in his position in 6 minutes = −10 ft
The change in diver's position during the descent (in 30 minutes) = 5 × (−10) ft = −50 ft
The final position of the diver after 30 minutes = (−5) + (−50) ft
= −(5 + 50) ft
= −55 ft
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